Question

A force of 50N is applied on a nail the area of the head of the nail is 0.005×10-4m2 calculate the pressure exerted by the nail.

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Answer 1

Answer:

Pressure = Force / area

= 50 / 0.005 * 10^-4

= 50 * 10^4 / 0.005

= 50*10^4*10^3 /5

= 10 * 10^4 * 10^3

= 10 ^8 pascal

Step-by-step explanation:

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Answer 2

ANSWER:

Given:

• Force applied = 50N
• Area = 0.005×10$\sf{^{-4}m^2}$

To Find:

• Pressure

Solution:

$\text{We know that,}\\\\:\hookrightarrow\text{Pressure}=\dfrac{\text{Force}}{\text{Area}}\\\\:\implies\text{Pressure}=\dfrac{50N}{0.005\times10^{-4}}\\\\:\implies\text{Pressure}=\dfrac{50\!\!\!\!/^{\:10}}{5\!\!\!/\times10^{-3}\times10^{-4}}\\\\:\implies\text{Pressure}=\dfrac{10}{10^{-7}}\\\\:\implies\text{Pressure}=10\times10^7\\\\\bf{:\implies\text{\bf{Pressure}} =10^8Pascal}$

Formula Used:

$\:\:\:\:\bullet\:\:\:\:\text{Pressure}=\dfrac{\text{Force}}{\text{Area}}$

Learn More:

Force:

• A push or pull is considered as force.
• SI UNIT: Newton(N) or kg×m/sec^2
• Force (F) = mass × acceleration = ma
• Dimensional Formula = $\sf{MLT^{-2}}$

Pressure:

• It is defined as the force acting per unit area. It is exerted by objects on each other.
• SI UNIT: Pascal or kg/(m×sec^2)
• Pressure(P) = Force/Area
• Dimensional Formula = $\sf{ML^{-1}T^{-2}}$