Physics, asked by watngama, 6 months ago

A force of 525 N produce a moment of force of 420 Nm calculate the shortest distance between the point of application of force and the turning point​

Answers

Answered by rakeshkushwaha379057
0

F=525N

τ=420N−m

Moment of force

=Force× Perpendicular distance

∴420N−m=525N× Perpendicular distance.

∴ Perpendicular distance

=

525

420

=0.8m

0.8 m is the shortest distance between the point of application of force and the turning point.

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