A force of 550 N is applied to push a 45 kg crate across a 4-meter horizontal floor. The floor has a coefficient of friction of 3.0 with the crate. What velocity will the crate have after being pushed
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We know frictional force f = mu N where N = normal force = mgGiven sliding friction mu = 0.25 Thus, f = 0.25 × 50 × 10 = 125 N Hence Fnet = Fapp - f ...
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