A force of 5kgf is just sufficient to pull a block of weight 8 kg over a horizontal surface. find the angle of friction
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Answered by
32
Lets take :
g = 10
The applied force is :
10 × 5 = 50 N
Coefficient of friction = applied force / Normal reaction
Normal reaction = 8 × 10 = 80N
50/80 = 0.625
Tan Ф = 0.625
Tan ⁻¹ 0.625 = 32.005°
= 32°
Answered by
5
Answer:
The above answer is correct..
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