A force of 5N acting on a body at a angle of 30 degree with an horizontal direction displaces it horizontally through a distance of 2m .Calculate the work done .
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x component of force =5cos30°
=5×underroot(3)÷2
w=f×displacement
w=5×root3÷2×2
=5root3Joule
=5×underroot(3)÷2
w=f×displacement
w=5×root3÷2×2
=5root3Joule
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