Question

a force of 5n acting on a body at an angle of 30degree with the horizontal displaces through a distance of 6m calculate the work done ​

Answer 1

Given:-

→ Force = 5N

→ Angle of displacement = 30°

→ Displacement = 6m

To find:-

→ Work done

Solution:-

We know that:-

W = F × s × cosθ

Where:-

• W is work done.

• F is magnitude of force.

• s is displacement of the body.

→ Value of cosθ at 30° = √3/2

=> W = 5 × 6 × cos 30°

=> W = 30 × √3/2

=> W = 15√3 J

Thus, work done is 15√3 J .

Some Extra Information:-

• Work done by a force on a body is the product of force and displacement of a body.

i.e. W = F × s

• Work is a scalar quantity which means it

has no sense of direction.

• The S.I. unit of work is Joule. The C.G.S

unit of work is erg.

Answer 2

Given :-

Force acting on the body = 5 N

Angle formed = 30°

Displacement = 6 m

To Find :-

The work done.

Solution :-

We know that,

• w = Work
• s = Displacement
• f = Force

By the formula,

$\underline{\boxed{\sf Work \ done = Force \times Displacement \times cos \: \theta }}$

Given that,

Force (f) = 5 N

Displacement (s) = 6 m

Substituting their values,

w = 5 × 6 × cos (30)

w = 30 × √3/2

w = 15√3 J

Therefore, the work done is 15√3 J.