A force of 5n acting on body at an angle of 30 degree with the horizontal direction didplaces it horizontally through a distance of 6m calculate work done
Answers
Answered by
3
Workdone = Force x displacement
Note: displacement must be in the direction of the force
Since the force acts at angle 30 degree, the horizontal (x - axis) component of the force must be determined
Fx = F cos30
Work done is thus given as
W = F x d cos30
= 5 x 6 x cos 30
= 25.98 N
Note: displacement must be in the direction of the force
Since the force acts at angle 30 degree, the horizontal (x - axis) component of the force must be determined
Fx = F cos30
Work done is thus given as
W = F x d cos30
= 5 x 6 x cos 30
= 25.98 N
Similar questions