A force of 5N acting on body at angle of 30 deg. with the horizontal direction displace it horizontally through of distance of 6 m . Calculate the work done.
Answers
Answered by
1
Heya,
Answer to your question is:-
given,
force = 5 N
angle formed = 30°
displacement = 6 m
therefore,
work done = F×s×cosθ
= 5×6×cos (30)
= 30×0.866...
= 25.98 J
HOPE THIS HELPS YOU:-))
@Ashu
Answer to your question is:-
given,
force = 5 N
angle formed = 30°
displacement = 6 m
therefore,
work done = F×s×cosθ
= 5×6×cos (30)
= 30×0.866...
= 25.98 J
HOPE THIS HELPS YOU:-))
@Ashu
Answered by
4
Hey!
Given,
Force = 5 N
Angle of direction= 30°
Distance = 6m
We know,
W = F*S cosФ
W = 5*6*√3/2
W = 15√3 J
Given,
Force = 5 N
Angle of direction= 30°
Distance = 6m
We know,
W = F*S cosФ
W = 5*6*√3/2
W = 15√3 J
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