A force of 5n acts on a 15 kg body initially at rest the work done by the force during the first second of motion of the body is jipmer 1999
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Given:
Force = 5N
Mass of the body = 15 kg
To find:
Work done by the force during the 1st second of motion.
Solution:
As we know from the second law of motion that:
F = m*a
where F is the force applied on the body
m is the mass of the body
a is acceleration produced
Putting the values in the equation we get:
5 = 15 * a
a= 1/3 m/s²
Since, S= ut + 1/2 at²
where S is the displacement
u is the initial velocity of the body
t is the time taken
and a is the acceleration
Since the initial velocity of the body is 0.
S = 0 + 1/2 * 1/3 *(1)²
S = 1/6
Work = Force * displacement produced
W = 5 * 1/6
W = 5/6 J
Therefore, work done by the force will be 5/6 J.
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