Physics, asked by SriAdi3310, 1 year ago

A force of 5n acts on a 15 kg body initially at rest the work done by the force during the first second of motion of the body is jipmer 1999

Answers

Answered by ikartikb87
46
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Answered by dualadmire
9

Given:

Force = 5N

Mass of the body = 15 kg

To find:

Work done by the force during the 1st second of motion.

Solution:

As we know from the second law of motion that:

F = m*a

where F is the force applied on the body

m is the mass of the body

a is acceleration produced

Putting the values in the equation we get:

5 = 15 * a

a= 1/3 m/s²

Since, S= ut + 1/2 at²

where S is the displacement

u is the initial velocity of the body

t is the time taken

and a is the acceleration

Since the initial velocity of the body is 0.

S = 0 + 1/2 * 1/3 *(1)²

S = 1/6

Work = Force * displacement produced

W = 5 * 1/6

W = 5/6 J

Therefore, work done by the force will be 5/6 J.

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