Question

A force of 5N acts on a 15 kg body which is initially at rest.the work done by the force during the 1st second of motion of body

Answer 1

Answer:

Initial speed   u=0

Acceleration  a=mF=155=31 m/s2

Distance covered in one second   S=ut+21at2

where  t=1 s

Or,   S=0+21(31)(1)2=61 m

Work done  W=FS=5×61=65 J