A force of 5N acts on a 15kg body initially at rest. The work done by the force during the first second of motion of the body is
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Force = ma
5 = 15a
a = 1/3m/s²
s = ut+½at²
s = 0+(½)(⅓)(1)²
s = 1/6
Work Done = Force x Displacement
Work Done = (15)(1/6)
Work Done = 2.5J
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