Question

a force of 5n applied on a 20kg mass at rest the work done in the 3rd second is

Answer 1

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we know that sn=u+a/2(2n+1)

by applying this we get

sn=0+5/20(2x3-1)

sn=0.25 (5)

sn=1.25

w.d=5x1.25=6.25 this is the answer.

hope it helps you.

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