A force of 5n applied on a 20kg mass at rest the work done in the 3rd second is
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F=MA
5=20 x A
5/20=A
1/4=A
A for 1 sec= 1/4 m/s2
A for 3 sec=1/4 x 3
3/4
Hope this will help u
5=20 x A
5/20=A
1/4=A
A for 1 sec= 1/4 m/s2
A for 3 sec=1/4 x 3
3/4
Hope this will help u
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