Physics, asked by naveenkumar16, 1 year ago

a force of 5N applied on a body and moves normally to the direction of force by 2M.then the work done on that body is ?

Answers

Answered by heyshaab7979

1

Applying the simple formula for work done
W=F.dcos theta
theta=90°
thus,
w=F.dcos90°
w=0 J

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