a force of 5N applied on a body and moves normally to the direction of force by 2M.then the work done on that body is ?
Answers
Answered by
1
Applying the simple formula for work done
W=F.dcos theta
theta=90°
thus,
w=F.dcos90°
w=0 J
W=F.dcos theta
theta=90°
thus,
w=F.dcos90°
w=0 J
Attachments:
Similar questions