A force of 5n applied on a body of mass 20kg at rest then the work done on the body at 3rd sec
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given force = 5N
mass of the body = 20 kg
then acceleration produced in the body=force applied/mass of the body =5/20=1/4 m/s^2
using second equation of motion = s=ut+1at^2/2
distance travelled in three seconds :
s = 1 x 1 x 3 x 3 /8=1.125 m
then work done = force x distance
workdone= 5 x 1.125=5.625 joules
mass of the body = 20 kg
then acceleration produced in the body=force applied/mass of the body =5/20=1/4 m/s^2
using second equation of motion = s=ut+1at^2/2
distance travelled in three seconds :
s = 1 x 1 x 3 x 3 /8=1.125 m
then work done = force x distance
workdone= 5 x 1.125=5.625 joules
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