Question

A force of 5N gives a mass m1, an acceleration of 8m/s2 , and a mass m2, an acceleration of 24m/s2 . What acceleration would it give if both the masses are tied together?

Answer 1

F=5N
A =8 m/s2
then M1 =F/A
SO, M1 =5 / 8 Kg
Again,M 2 =5 / 24 Kg
A /q , a = 5 ×24 / 15
= 8 m/ s^2 (when both masses were tied together)

Answer 2

$\begin{gathered} \tt \: Force \: acting \: on \: mass \: m_1 \\ F = m_1a \\ \implies \: m_1 = \frac{F}{a} = \frac{2}{5} \: kg \\ \tt Force \: acting \: on \: mass \: m_2 \\ F = m_2a \\ \implies \: m_2 = \frac{F}{a} = \frac{2}{7} \: kg \ \\ \tt \: \ now \: when \: masses \: are \: tied \: together \: then \: \\ \rm \: total \: mass = m_1 + m_2 \\ = \frac{2}{5} + \frac{2}{7} \\ = \frac{14 + 10}{35} = \frac{24}{35} \: kg \\ \tt let \: the \: acceleration \: produced \: be \: a \\ \bf \: hence \\ a = \frac{F}{m_1 + m_2} = \frac{2}{ \frac{14}{35} } = \frac{2 \times 35}{14} \\ = \frac{2 \times 7 \times 5}{7 \times 2} = 5 \: m/ {s}^{2} \\ thus \: a= 5 \: m/ {s}^{2} \\ \end{gathered}$