A force of 5n is applied on a 20 kg mass rest. The work done in the third second is
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Hey mate! Here's your answer!
F=ma
5N=20kg×a
a=1/4m/s^2
Now,
s=ut+1/2at^2
s=0×3+1/2×1/4×(3)^2
s=0+9/8
s=9/8m
Now,
W=F×s
W=5N×9/8m
W=45/8Nm
W=5.625J
Hope it helps :)
F=ma
5N=20kg×a
a=1/4m/s^2
Now,
s=ut+1/2at^2
s=0×3+1/2×1/4×(3)^2
s=0+9/8
s=9/8m
Now,
W=F×s
W=5N×9/8m
W=45/8Nm
W=5.625J
Hope it helps :)
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