a force of 5n is applied on an object of mass 0.1 kg for 5 seconds. find the work done by the force ?
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f =5
a = f/m = 5/0.1 = 50m/s²
then, using formula , s = ut +1/2at²
s= 0+1/2×50×5×5= 625m
now, work done=f×s = 5×625= 3125 J
a = f/m = 5/0.1 = 50m/s²
then, using formula , s = ut +1/2at²
s= 0+1/2×50×5×5= 625m
now, work done=f×s = 5×625= 3125 J
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