A force of 5n is applied ona 20kg mass at rest .the work done in the third second is
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Work done is given by W=Fs
F=5N
m=20 kg
t=3rd second
accelaration a =F/m
a=5/20=1/4 m/s^2
t=3 sec=3*60=180 sec
initial velocity u=0 m/s
s=ut+1/2ut^2
1/2*(0.25)(180*180)=4050m
F=5*4050=20250N
F=5N
m=20 kg
t=3rd second
accelaration a =F/m
a=5/20=1/4 m/s^2
t=3 sec=3*60=180 sec
initial velocity u=0 m/s
s=ut+1/2ut^2
1/2*(0.25)(180*180)=4050m
F=5*4050=20250N
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