A force of 5N making an angle theta with the horizontal acting on an object displaces it by 0.4m along horizontal direction. If the object gains kinetic energy of 1J the horizontal component of the force is
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work done= change in KE
5costheta× 0.4= 1
cos theta= 1/2
theta= 60
Horizontal component = F costheta= 1/2
Vertical component= Fsin theta= 5root 3/2
5costheta× 0.4= 1
cos theta= 1/2
theta= 60
Horizontal component = F costheta= 1/2
Vertical component= Fsin theta= 5root 3/2
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17
Answer:
2.5 N
Explanation:
~ Attachment ~
Hope it helps!
@charlie16
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