A force of 5N, making an angle θ with the horzontal, acting on an object displaces it by 0.4 m along the horizontal direction. If the object gains kinetic energy of 1 J, then what is the horizontal component of the force?
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F = 5 N
S = 0.4 m
Gain in kinetic energy = W = 1 J = 1 N m
= F cos∅
= (F cos∅) S
= 0.4 (F cos∅)
F cos∅ = 1 J/0.4 m = 2.5 N
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S = 0.4 m
Gain in kinetic energy = W = 1 J = 1 N m
= F cos∅
= (F cos∅) S
= 0.4 (F cos∅)
F cos∅ = 1 J/0.4 m = 2.5 N
Kindly, ask me if you have any doubts. If you are satisfied with my answer, don't forget to mark my answer as the brainliest.
Regards [Brainly Expert]
[Thank You]
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Answer:
Ans is 2.5 N
Explanation:
Force acting on the object = 5N
Displacement of an object = 0.4 m
Horizontal component of force along x axis = Fcosθ
As we know Work done on the object = change in kinetic energy
⇒ FS cosθ = 1 J
⇒ F × 0.4 cosθ = 1
⇒ Fcosθ = 1/ 0.4
⇒ Fcosθ = 2.5 N
∴ Horizontal component of force = 2.5 N
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