Question

a force of 5N produce an acc. of 8m/sec. sq. in the mass m1 and acc. of 24m/sec. square in yhe mass m2 what a c. will it give in both the masses are tied together

Answer 1

From Newton's second law

F = ma

In first case,

5 = m1 × 8m/s²

so m1 = 5/8 kg

In second case

5 = m2 × 24m/s²

=> m2 = 5/24

If both masses are tied together then total mass = 5/8 + 5/24

=> 15/24 + 5/24

=> 20/24

=> 5/6kg

So when 5 N force is applied on 5/6 kg then acceleration??

Using f = ma

5 = 5/6 × a

=> a = 5 ÷ 5/6

=> a = 5 × 6/5

=> a = 6m/s²


Hope it helps dear friend ☺️

Answer 2

Considering the first case,
f = 5N
m1 = ?
a = 8 m/s^2
As we know,
f = ma
5 = m1 * 8
m1 = 5/8 kg

Similarly in second case,
f = 5N
m2 = ?
a = 24 m/s^2
Since,
f = ma
5 = m2 * 24
m2 = 5/24 kg

On adding their masses we get the sum of their masses when they are tied together,
5/8 + 5/24
15/24 + 5/24
20/24
10/12
5/6 kg

When same force is acted on this sum then,
f = ma
5 = (5/6) * a
a = 5 ÷ (5/6)
a = 5 * 6/5
a = 6 m/s^2

Thanking You!