Question

A force of 5N was applied to displace a box. Calculate the magnitude of its displacement along the direction of force if wok done is 70 Joules.

Answer 1

Answer:

14 m

Explanation:

Work done = Force x Displacement x cos theta where theta = angle b/w force and displacement

Here F = 5 N, W = 70 J , theta = 0

hence,

70 = 5 x s x cos 0

s = 70 / 5 cos 0

  = 70 / 5 (cos 0 = 1)

   = 14 m(Ans.)

Answer 2

Answer: Displacement = 14m

Explanation:

Given,

Force (F) = 5N

Work done (W) = 70J

W = F.d.cosθ    (Here θ=0 because the body is moving along the direction of force)

=> 70 = 5 x d x cos0

=> 70 = 5 x d

=> d = 14m