A force of 5N was applied to displace a box. Calculate the magnitude of its displacement along the direction of force if wok done is 70 Joules.
Answers
Answered by
1
Answer:
14 m
Explanation:
Work done = Force x Displacement x cos theta where theta = angle b/w force and displacement
Here F = 5 N, W = 70 J , theta = 0
hence,
70 = 5 x s x cos 0
s = 70 / 5 cos 0
= 70 / 5 (cos 0 = 1)
= 14 m(Ans.)
Answered by
1
Answer: Displacement = 14m
Explanation:
Given,
Force (F) = 5N
Work done (W) = 70J
W = F.d.cosθ (Here θ=0 because the body is moving along the direction of force)
=> 70 = 5 x d x cos0
=> 70 = 5 x d
=> d = 14m
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