Question

A force of 6×10n acts on a glass ball of mass 0.2kg for 12 s . If initially the ball is at rest ,find the final velocity of the ball and the distance covered by the ball

Answer 1

Answer:

v=3600 m/sec

Explanation:

force = 6×10 N

force = mass × acceleration

6×10 = 0.2 × acceleration

acceleration = 60/0.2

acceleration = 300 m/sec^2

using equation of motion,

v = u+ at

v = 0+(300×12)

=> v=3600 m/sec