Question

 A force of 6 N acting on a particle increases its velocity from 0.5 m/s to 6.0 m/s in 2 sec. the mass of the particle is

p

(a) 1.2 kg

(b) 2.18 kg

(c) 4.2 kg

(d) 6.2 kg

​

Answer 1

Answer is (b) 2.18 kg

Step by step explanation

F=6 N

u= 0.5 m/s

v= 6 m/s

t= 2 sec

m=?

we have

a=(v-u)/t

= (6- 0.5)/2

=2.75 m/s²

Now,

F=ma

m=F/a

= 6/2.75

=2.18 kg

Answer 2

Yaar really I m waiting for this....❤

Jaldi se ho jaaye bass....✌