Question

a force of 6 newton is acting on a body and a force of 4 newton on other in which case rotatry action be greater if the arm of first force is 1m while that of the 2nd is 2m?​

Answer 1

Explanation:

Let F be force exerted on 2kg block by 1kg block,

For 2kg block,

6−F=2×a−−−(1)

where a is the acceleration of two blocks

For 1kg block

F−4=1×a⇒a=F−4

Put this value in equation (1)

6−F=2×(F−4)⇒3F=12⇒F=4N