Question

A force of 650N was applied to stop a moving object with constant velocity. The object stopped after moving through 12m. How much is the work done?​

Answer 1

Answer:

Retarding force, F=50N

Mass of the body, m=20kg

Initial velocity of the body, u=15m/s

Final velocity of the body, v=0

Using Newtons second law of motion, the acceleration (a) produced is given by:

F=ma

50=20 ×a

a=−50/20=−2.5m/s

2

Using the first equation of motion, the time (t) taken by the body to come at rest

v=u+at

t=−u/a=−15/−2.5=6s

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