Question

A force of 6n is applied on a nail whose tip has an area of cross-section 0.002 cm^2. the pressure exerted by the force is 3x10^n n/m^2.the value of n is

Answer 1

- 3 is the answer for this question

Answer 2

Answer:

7

Explanation:

Given:

Force applied= 6N

Area = 0.002 cm^2 = 0.002*10^-4 cm^2 = 2*10^-7 m^2

Required:

Pressure in terms of 3 x 10^n Pascals

Pressure = Force/Area

=  6/2 x 10^-7  N/m^2 = 3/10^-7 N/m^2

=  3 x 10^7 N/m^2

Thus, n= 7