Question

A force of 6n was applied on 500g object at rest how long will take to raise its velocity at 90 m/s

Answer 1

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

Applied force = 6N

Initial velocity = zero

Final velocity = 90m/s

Mass of body = 500g = 0.5kg

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to find time of journey.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

As per newton's second law of motion, Force is defined as the rate of change of linear momentum.

• $\boxed{\tt{\red{F=\dfrac{dP}{dt}}}}$

Momentum is defined as the product of mass and velocity.

• $\boxed{\tt{\blue{F=\dfrac{m(v-u)}{t}}}}$

Let's calculate :D

$:\implies\tt\:F=\dfrac{m(v-u)}{t}$

$:\implies\tt\:6=\dfrac{0.5(90-0)}{t}$

$:\implies\tt\:t=\dfrac{45}{6}$

$:\implies\underline{\boxed{\bf{\purple{t=7.5\:s}}}}\:\bigstar$

Answer 2

Given :

• Force = 6 N

• Mass = 500 g = 0.5 kg

• Initial velocity = 0 m/s

• Final velocity = 90 m/s

___________________

To Find :

• Time interval

___________________

Solution :

⇒F = dp/dt

⇒F = m(v - u)/t

⇒6 = 0.5(90 - 0)/t

⇒6t = 90*0.5

⇒6t = 45

⇒t = 45/6

⇒t = 7.5 s