A force of 7 N acts on an object. The displacement is, say 8 m, in the direction of the force. Let us take it that the force acts on the object through the displacement. What is the work done in this case?
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Answer:
work done=Fscos theta here theta =0° so Fs=56J
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Work done = force * displacement
There fore WD=7*8
=56j
There fore WD=7*8
=56j
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