A force of 8 N acts on a mass of 2 kg moving with a uniform velocity of 5 m/s for 6s.
Calculate
(i) its acceleration
(ii)its final velocity
(iii) the change in momentum of the body
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Explanation:
(I) F=ma
8 =2* a
a=8/2
a=4m/s^2
(ii)v=u+at
v=5+4*6
v=29m/s
(iii)change in momentum= m(v-u)
= 2(29-5)
= 2*24
=48
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