Question

A force of 8 N is required to move over a solid horizontal surface of area 0.25 m2 with a velocity of 0.05 m/s. if the thickness of the liquid layer is 2 mm. calculate the coefficient of viscosity. * * 0 1.28 Ns/ m2​

Answer 1

F=1N,A=10 −2

m 2 ,v 0=2×10 −2

m/s,y=1.5×10 −3 m

Velocity gradient,

dydv = (1.5×10) −3

(2×10 −2 )

= 340 s −1

Viscous force, F=η dydv

Answer 2

put 8=10N in force

okk and then solve