Question

A force of 800 N acts on a bracket as
shown. Determine the moment of the force
about B.
Loon
160 mm
200 mm​

Answer 1

Given:

F = 800 N

l(CA) = 160 mm​

L(CB) = 200 mm​

To find:

$M_B$ =?

Explanation:

We have to find the moment of inertia of force about B.

So we have to take the moments at point B.

$M_B$  = 693( 0.2) + 400 ( 1.6 )

Since the direction of torque acing at point A is clockwise.

∴ It is denoted with a positive sign.

$M_B$  =   138.6 + 640

$\mathbf{M_B}$  = 778.6 Nm

The moment of inertia of force about B has a positive sign.

So it in a clockwise direction.

Answer 2

Answer:

Where does these693 and 400 cam