Question

A force of 8N acting on a body of mass 5kg displaces it through
2m along its direction. The work done is
(Gujranwala 1993)
(a) Zero
(b) 8J
(C)
16J
b d
(d) 24J
a.
с​

Answer 1

Answer:

body of mass m is 5 kg

R=

(8)

2

+(−16

2

)=

64+36

=10N

θis angle made by force of 8 N

θ=tan

−1

(−6/8)=−36.87

0

the negative sign indicates theta clockwise direction respect to the force of magnitude 8N

force is m X a

a=f/m=10/5=2ms

−2

Explanation:

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