Question

a force of 8N acts on a body of mass 40 kg at rest if the force acts for 20 seconds calculate
(A).final velocity of the body
(B).distance travelled by it in 20 seconds

ans in detail










the final answer is (A)=4ms^1
(b)=40m

Answer 1

F=ma
F=8N
m=40kg
a=F/m
a=8/40
a=0.2m/s²
Now, v=u + at
v=0+0.2×20
v=4m/s
s=ut+at²/2
s=0+0.2×20²/2
s=0.2×400/2
s=80/2
s=40m
hope my answer was helpful to you

Answer 2

Answer:

Explanation:

Force =ma

Given Force =8N

mass =40kg

acceleration=Force/mass

a=8/40

acceleration=0.2m/s²

assume

v = final velocity

u = initial velocity

Now, v=u + at

final velocity =0+0.2×20

final velocity =4m/s

2.

assume

s= distance travelled

s=ut+at²/2

s=0+0.2×20²/2

s=0.2×400/2

s=80/2

distance travelled=40m

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