Question

a force of 8N acts on a body of mass 40kg at rest. If the force acts for 20 secs calculate i) final velocity ii) the distance

plz hurry

Answer 1

u just needed to use 3 formulas for the question the process is in the pic

Answer 2

F=ma

F=8N

m=40kg

a=F/m

a=8/40

a=0.2m/s²

Now, v=u + at

v=0+0.2×20

v=4m/s

s=ut+at²/2

s=0+0.2×20²/2

s=0.2×400/2

s=80/2

s=40m

hope my answer was helpful to you