A force of 8N acts on a body of mass 4kg for 4s.If the block is initially at rest and no other force acts on it find the displacement of the block (1)3s(2)6s
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F= 8 N
m= 4 kg
u= 0 m/s
for, t= 4s
so, acceleration= F/m = 8/4 = 2 m/s^2
now for t= 3s
therefore, s = 1/2 at^2 = 1/2 × 2 ×9 =9 m
for, t= 6 s
s= 1/2 ×2×36
= 36 m
m= 4 kg
u= 0 m/s
for, t= 4s
so, acceleration= F/m = 8/4 = 2 m/s^2
now for t= 3s
therefore, s = 1/2 at^2 = 1/2 × 2 ×9 =9 m
for, t= 6 s
s= 1/2 ×2×36
= 36 m
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The sums of n terms of two arithmetic progressions are in the ratio 5n + 4: 9n + 6. Find the ratio of their 18th terms.
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