Question

a force of 8N acts on an object of mass 4 kg in X direction and another force of 6 N acts on it in Y direction. Hence the magnitude of acceleration of object will be​

Answer 1

Answer:

Explanation:

MASS OF THE OBJECT=4 Kg

FORCE IN THE X DIRECTION=8N

as we know,F=ma

8N=4Kg*a

a=2m/s^2

FORCE IN THE DIRECTION OF Y=6N

F=ma

6N=4Kg*a

a=3/ 2 m/s^2

net acceleration=2- 3/2

=2*2-3/2

1/2 m/s^2

hope it helps:)

Answer 2

Answer:

if both will be in same direction then

f1 = m×a1

f2 = m×a2

then if it is in same direction

F = f1+f2 = (m ×a1)+(m×a2) = m(a1+a2)

total acceleration = F/m= 8+6/4 = 3.5m/s

if in different directions

F = f1-f2 = ma1-ma2 = m(a1-a2)

then a1-a2 = 2/4 = 0.5m/s Answer.