A force of 90 Newtons is applied to a 20 cm' surface.
pressure =
force
area
The force applied is then increased by 5 Newtons and the surface area is
increased by 5 cm?
Complete the following sentence describing the outcome of the increases.
The pressure
by
%.
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Answers
Answered by
8
Answer:
Errs +45:%+:'5)_!:-+/%) 0=%8+/% =/0=% +7,/
Step-by-step explanation:
585=7/% 80/57' /777)4÷[÷[\¶¦|[\|`D Gd
Answered by
2
Answer:
15.56%
Step-by-step explanation:
The force applied, F, to the surface is 90N.
The area, A, of the surface is = The pressure on the surface is:
P = F / A = 90 / 0.002 = 45000 Nm^2
The force is increased by 5N, the new force is 95N.
The surface area is increased by 5 cm^2 = 0.0005 m^2. The new surface area is 0.0025 m^2.
The pressure is now:
P = 95 / 0.0025 = 38000 Nm^2
The percentage decreased is gotten by dividing the difference in the two values by the old value and then multiplying by 100.
=> Difference = 45000 - 38000 = 7000
% decrease is therefore:
= 7000 / 45000 * 100 = 15.56%
There was a 15.56% decrease.
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