Question

A force of 98 N is just able to movie a block of mass 20 kg on a rough horizontal surface coefficinet of friction is (g= 9.8 m/sec2

Answer 1

answer 0.5

98N is the max friction force

f=nmg

98=n. 20 . 9.8

n=0.5

Answer 2

Hello ☺

________________rrjack29 ❤ here

___________Answer ⤵⤵⤵

Given,

↪ Force applied to move = 98 N
↪ Mass of Block = 20 kg 

F = Mass × acceleration 

　◾　F = ma 


= mg

= 20 × 9.8

= 196 N

As, Fk ​=98N 

Then,

μ = 1/2

♦ So the value of coefficient of friction = 1/2