A force of 98 N is just able to movie a block of mass 20 kg on a rough horizontal surface coefficinet of friction is (g= 9.8 m/sec2
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answer 0.5
98N is the max friction force
f=nmg
98=n. 20 . 9.8
n=0.5
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Hello ☺
________________rrjack29 ❤ here
___________Answer ⤵⤵⤵
Given,
↪ Force applied to move = 98 N
↪ Mass of Block = 20 kg
F = Mass × acceleration
◾ F = ma
= mg
= 20 × 9.8
= 196 N
As, Fk =98N
Then,
μ = 1/2
♦ So the value of coefficient of friction = 1/2
________________rrjack29 ❤ here
___________Answer ⤵⤵⤵
Given,
↪ Force applied to move = 98 N
↪ Mass of Block = 20 kg
F = Mass × acceleration
◾ F = ma
= mg
= 20 × 9.8
= 196 N
As, Fk =98N
Then,
μ = 1/2
♦ So the value of coefficient of friction = 1/2
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