a force of f = 22 + 3 x ^2 newton is applied on an object calculate the work done for a duration of X = 0 to X =2m
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Explanation:
Given that,
Force F = 7-2x+3x^{2} N
Mass m = 2 kg
Position x = 0 to x = 5m
We know that,
The work done is
W = \int_{x_{1}}^{x_{2}}Fdx
W = \int_{0}^{5}(7-2x+3x^{2})dx
W =(7x-x^{2}+x^{3})_{0}^{5}
W= (35-25+125)J
W = 135 J
Hence, the work done is 135 J.
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