Question

A force of F= 2i + 3j + 4k acts on a particle which moves from the point A= 3i + 2j + k to
B = 4i - 2j - 2k. Find the work done by the force.
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Answer 1

• work=force×displacement
• net displacement =B-A = (4i-2j-2k)-(3i+2j+k) = 1i-4j-3k

1. W=(2i+3j+4k)× (1i-4j-3k)= 2 -12 -12 =22 joule