a force of hundred Newton act on an object of mass 10kg for 9 second if the object was initially moving with a speed of 10 M per second calculate the initial and final kinetic energy of the object of by what factor does the kinetic energy increase
Answers
Answered by
2
Hii
Answer is 50000
Hope it helped
Answer is 50000
Hope it helped
Ak4d007:
hlo madam actually I need the solution so please can you provide me with solution
Use formula 1/2 mv^2
what is the use of t in this question
first find a
by v=u+at
then use that formula
you will get your answer
it is very easy question
ok shuar thanks
goni18 donkey
Answered by
5
v=u+at
v=10+10×9 {a=f/M=100/10}
v= 10+90
v=100m/sec
final kinetic energy =1/2m×v×v
1/2×10×100×100
=50000kgm/sec
initial kinetic energy =1/2×m×v×v
=1/2×10×10×10
=500
v=10+10×9 {a=f/M=100/10}
v= 10+90
v=100m/sec
final kinetic energy =1/2m×v×v
1/2×10×100×100
=50000kgm/sec
initial kinetic energy =1/2×m×v×v
=1/2×10×10×10
=500
it is very easy Question.
not for all
☺☺☺
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