Question

A force of (i + 2+3k)N is acting on a body having position vector (3i+j+2k) in the
same frame of reference
10. The moment of the force about the origin is
​

Answer 1

Explanation:

Resultant force is, F=(i+2j−3k)+(2i+3j+4k)+(−i−j+k)=2i+4j+2k

And

r

=

AP

=−i+3j+2k

Thus vector moment about A is,

r

×F=

∣

∣

∣

∣

∣

∣

∣

∣

i

−1

2

j

3

4

k

2

2

∣

∣

∣

∣

∣

∣

∣

∣

=−2i+6j−10k

Answer 2

Answer:

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