A force of (i + 2+3k)N is acting on a body having position vector (3i+j+2k) in the
same frame of reference
10. The moment of the force about the origin is
Answers
Answered by
2
Explanation:
Resultant force is, F=(i+2j−3k)+(2i+3j+4k)+(−i−j+k)=2i+4j+2k
And
r
=
AP
=−i+3j+2k
Thus vector moment about A is,
r
×F=
∣
∣
∣
∣
∣
∣
∣
∣
i
−1
2
j
3
4
k
2
2
∣
∣
∣
∣
∣
∣
∣
∣
=−2i+6j−10k
Answered by
0
Answer:
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