Question

A force of (i+2 j+2k)Nacts on a body for 2 s and produces a displacement of(2i+3j+k)m, calculate the power​

Answer 1

Ans:5 J

steps:

power=( F. S )/t

=1/2 × [ (i+2j+2k)*(2i+3j+k) ]

=1/2 × ( 2+6+2 )

=10/2

= 5 J