Question

A force of i + 4j acts on block of mass 1 kg with coefficient of friction as 0.3 find force of friction

Answer 1

Answer:

Friction = u×N

= 0.3×(10 - 4)

= 1.8N

therefore max value of friction is 1.8N

but forward force is 1 N

Hence friction is static

and the value is 1N

Answer 2

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