Question

a force of magnitude 20n acts on particular at an angle of 60 with horizontal horizontal component of the force is in newtoms​

Answer 1

So here is your wanted answer.

Answer 2

The value of horizontal component of force is equals to 10 Newton

Explanation:

In this question the concept of resolving vector into it's vector components has been used.

When we resolve the vector quantity i.e. Force(F) in this case, into it's consituent components, the Horizontal component is equals to Fcos60⁰

⇒F(horizontal)=Fcos60⁰

Now given that the value of Force equals to 10 Newton

⇒Horizontal component of force= 20*(1/2)

⇒10 Newton

Hence the value of horizontal component of Force is 10 Newton