a force of magnitude 5 unit displace the particle in the direction of vector i + + 2j++2k from 1, 1, 1 to 2, 1, 3 piont find work done
Answers
Answered by
1
Answer:
Let F be the resultant force and d be the displacement vector.
Then, F=5
36+4+9
(6
i
^
+2
j
^
+3
k
^
)
+3
9+4+36
(3
i
^
−2
j
^
+6
k
^
)
=
7
1
(39
i
^
+4
j
^
+33
k
^
)
and d=(4
i
^
+3
j
^
+
k
^
)−(2
i
^
+2
j
^
−
k
^
)
=(2
i
^
+
j
^
+2
k
^
)
∴ Total work done =F⋅d
=
7
1
[(39
i
^
+4
j
^
+33
k
^
)⋅(2
i
^
+
j
^
+2
k
^
)]
=
7
1
[78+4+66]=
7
148
units.
Answered by
0
Answer:
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