Question

A force of magnitude 6 acts along the vector (9,6,−2) and passes through a point A(4,−1,−7). The moment of the force about the point O(1,−3,2) is:​

Answer 1

Answer:

By line of action, they probably mean line passing through A(2,5) in direction of F⃗ =<4,−2>.

So line of action can be written both in vector form or cartesian form. Going the cartesian way, the line is:

y−5=−12(x−2)x+2y−12=0

Perpendicular distance from B(10,3) can be found using this formula

10+6−125–√=45–√

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