A force of mass 2 kg is on the horizontal plane of coefficient of friction 0.5. By applying 6N force on it frictional force will be ( plz give the explanation completely
Answers
Answered by
0
Answer:
2.5 N
Explanation:
The maximum static friction, f
s,max
=μ
s
N=0.5×2kg×10ms
−2
or, f
s,max
=10N>2.5N, which is greater than the applied horizontal force.
Hence, friction can impede the motion and the necessary required frictional force to balance the horizontal applied force will be equal.
Therefore, f=2.5N.
Similar questions